Question 470963
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Hi,
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p = .6(red)& q = .4
nCx = {{{n!/(x!(n-x)!)}}}  n = 4
P(3 or 4 red) = P(3red) + P(4red) = 4(.6)^4*.4 + (.6)^4 = .4752 
sry, did not read it properly: 
 47.52% of the  samples contain at least 3 red.