Question 470909
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Hi,
get 10 liters 
Let x and (10L-x) represent the amounts of the 50% and 20% solutions respectively
Mixing
  .5x + .2(10L-x) = .30*10L
        .3x = .28*10L
          x = 9 1/3L of 50% and 2/3L of the 20% need to be mixed