<PRE><B>Question 48774</B>
A rectangular parking lot is 50 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 250 ft diagonally
LET LENGTH =L
WIDTH=W
L=W+50
DIAGONAL^2=L^2+W^2
250^2=(W+50)^2+W^2=W^2+100W+50^2+W^2=2W^2+100W+2500
2W^2+100W+2500-62500=0
W^2+50W-30000=0
W^2+200W-150W-30000=0
W(W+200)-150(W+200)=0
(W-150)(W+200)=0
W=150
L=200
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