Question 470899
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Hi,
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p = .09 q = .91   n = 6
nCx = {{{n!/(x!(n-x)!)}}}
P(exactly 2 out of 6 men...) = 6C2(.09)^2(.81)^4 = 15(.09)^2(.91)^4 = .0833