Question 470836
Let x is the length of a rectangle
The width of a rectangle is three-fourths its length, so the width is {{{(3/4)x}}}
The diagonal is 10 inches, use the Pythagorean theorem {{{x^2+((3/4)x)^2=10^2}}}
{{{x^2+(9/16)x^2=100}}}
{{{((16+9)/16)x^2=100}}} multiply by 16
{{{25x^2=1600}}} divide by 25
{{{x^2=64}}}
{{{x=8}}} inches is the length of a rectangle
{{{(3/4)x=(3/4)*8=3*2=6}}} inches is the width of a rectangle