Question 470791
{{{y^2=(3/5)y+2/3}}}

LCD = 15
{{{15y^2=9y+10}}}
{{{15y^2-9y-10=0}}}
Find the roots of the equation by quadratic formula							
							
a=	15	b=	-9	c=	-10		
							
b^2-4ac=	81	-	600				
b^2-4ac=	681		
{{{sqrt(	681)}}}=	26.1
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(9+26.1)/30		
x1=1.17	===>	7/6				
x2=(	9	-26.1	) /	30			
x2= 	-0.57===>	- 4/7