Question 470669
the perimeter of the rectangle is {{{P=2L+2W}}}, where L is the length, W is the width of the rectangle
The perimeter of the first rectangle is {{{P1=2l+2w=2(l+w)}}}units
The perimeter of the second rectangle is {{{P2=2*2l+2*4w=4(l+2w)}}}units
the perimeter of the second rectangle is much larger than the perimeter of the first rectangle {{{(P2)/P1=(4(l+2w))/(2(l+w))=(2(l+2w))/(l+w)}}} times