Question 469747
{{{x^2-3x-10=0}}}
{{{ax^2+bx+c=0}}}
a=1
b=-3
c=-10
 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
 {{{x = (3 +- sqrt( 9+40))/(2) }}} 
 {{{x = (3 +- sqrt( 49))/(2) }}} 
 {{{x = (3 +- 7)/(2) }}} 
 {{{x = (3 +7)/(2) }}}
  {{{x = 5 }}}
or
 {{{x = (3 - 7)/(2) }}} 
{{{x = -4/2 }}}
{{{x=-2}}}