Question 470636
{{{(1/3+ (sqrt( 10 )/6) i)^2}}}
Use formula {{{(a+b)^2=a^2+2ab+b^2}}}
{{{(1/3)^2+2*(1/3)*(sqrt(10)/6)i+((sqrt(10)/6)i)^2=1/9+((2*sqrt(10))/(3*6))i+(10/36)(i)^2=1/9+((sqrt(10))/9)i-5/18=-1/6+(sqrt(10)/9)i}}}