Question 470667
(7/(6p^2*q))/(14/(18p^2*3q))
use the formula of dividing two fractions  {{{(a/b)  / (c/d)}}} = {{{a/b *d/c}}}

then:
{{{7/(6p^2*q)*(18p^2*3q)/14}}} = {{{1/(6p^2*q)*3(6p^2*q)/2}}}={{{3/2 }}}