Question 470613
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
Event A, 3 on the 1st roll  P(A) = 6/36 = 1/6
Event B, sum is 7    P(B) = 6/36 = 1/6
Event C, double      P(C) =  6/36 = 1/6
If events are independent, then the probability of them both occurring is the
 product of the probabilities of each occurring. 
P(A and B)= P(A)*P(B) = 1/6*1/6 = 1/36 = P(both occur) a 3 rolled and then a 4
  Events A and B are Independent  
___1_2_3__4__5__6  (First roll)
1|_2_3_4__5__6__7
2|_3_4_5__6__7__8
3|_4_5_6__7__8__9
4|_5_6_{{{highlight(7)}}}__8__9_10
5|_6_7_8__9_10_11
6|_7_8_9_10_11_12