Question 470579
{{{x ^3+ 2x^2- 16x - 32 = 0}}}
{{{x^2(x+2)-16(x+2)=0}}}
{{{(x+2)(x^2-16)=0}}}
{{{x+2=0}}} or {{{x^2-16=0}}}
{{{x=-2}}} or {{{x^2=16}}}
{{{x1=-2}}}, {{{x2=4}}}, {{{x3=-4}}}