Question 470581
4	x	+	3	y  	=	1				
Find the slope of this line 						
3y =	-4	x	+	1				
Divide by 	3									
	y  	=	-4/3	x	+	0.33				
Compare this equation with y=mx+b										
slope m =	-4/3	
The slope of a line perpendicular to the above line will be the negative reciprocal = 3/4										
m1*m2=-1										
The slope of the required line will be 			0.75			0.75	=	0.75		
										
m=	 3/4	,point	(-1,2)			
Find b by plugging the values of m & the point in										
y=mx+b										
2=-0.75	+	b						
b=	2.75= 9/4									
m=	 3/4									
The required equation is	y= 3/ 4	x+9/4