Question 470288
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Hi,
Question states***
sqrt(x+3)=x+1
   (x+3) = (x+1)^2
   x+3 = x^2 + 2x+ 1
   x^2 + x - 2 = 0
factoring
  (x +2)(x-1) = 0
  (x +2)= 0   x = -2
  (x-1) = 0   x = 1

CHECKING our Answers***
  sqrt(1)&#8800; -1, x= -2 is an Extraneous solution
  sqrt(4) = 2   x = 1 is the Solution