Question 470029
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Since the given equation is in slope-intercept form, determine the slope of the graph of the given equation by inspection of the coefficient on *[tex \Large x].


Use the principle that the slopes of perpendicular lines are negative reciprocals of each other, which is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \neq\, 0]


to calculate the slope of the graph of the desired equation.


Use the point-slope form of the equation of a line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the calculated slope.


Manipulate the result to obtain the slope-intercept form, namely *[tex \Large y\ =\ mx\ +\ b]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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