Question 469972
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Hi,
{{{(x-6)/(x^2-7x+12) = (x-6)/((x -3)(x-4))}}}
Undefined when the denominator = 0  CANNOT divide by zero
(x-3)(x-4) = 0
(x-3)= 0
(x-4)= 0
 {{{(x-6)/(x^2-7x+12)}}} is undefined for x = 3  and x = 4