Question 469930
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
Find a quadratic equation for the solutions of 1/3 and 5
 (x-1/3)(x-5) = 0
F	First terms
O	Outside terms
I	Inside terms
L	Last terms
  x^2 - 1/3x - 5x + 5/3 = 0
  x^2 - (16/3)x + 5/3 = 0
 3x^2 -16x + 5 = 0
 y =  3x^2 -16x + 5 

{{{drawing(300,300,   -6, 6, -6, 6,  grid(1),
circle(1/3, 0,0.3),
circle(5, 0,0.3),
graph( 300, 300, -6, 6, -6, 6,0,3x^2-16x+5))}}}