Question 48706
What amount of each mixture, one 95% alcohol and the other 15% alcohol, must be used to make 10 liters of a mixture which is 45% alcohol? What equation or equations will express this problem?

95% mixture DATA:
amount = x liters ; active ingredient= 0.95x
-----------------------
15% mixture DATA:
amount = 10-x liters ; active ingredient = 0.15(10-x)
------------------------
45% mixture DATA:
amount =10 liters ; active ingredient = 0.45(10)
-------------------------
EQUATION:
active + active = active
0.95% + 0.15(10-x)= 0.45(10)

Looks like "C" is the answer.

Cheers,
Stan H.