Question 469885
{{{sqrt(x+3)= x+1}}} square each side and you get
{{{x+3= x^2+2x+1}}}
{{{0= x^2+x-2}}} 
{{{0= (x+2)(x-1)}}}  
x+2=0
x=-2
x-1=0
x=1
so solutions are x=-2 or x=1