Question 469839
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Hi
{{{a^0 = 1}}}
{{{(a^p)^q = a^(p*q)}}}
{{{root(a,p)*root(a,q) = root(a,p*q)}}}
{{{x^m/x^n=x^(m-n)}}}
{{{( x^m )( x^n ) = x^( m + n )}}}
Applying the above appropriately
1){{{x^3* y^5* y^-7/ x^5}}} = {{{(x^-2)(y^-2)}}}
2)z^16.z^-16 = z^0 = 1
3){{{y^43 / y^24}}} = y^19
4)[(xy)^4]^3 = {{{(x^12)(y^12)}}}
5)[(st)^2s^3]^4= [s^2t^2s^3]^4 = [s^5t^2]^4 = {{{(s^20)(t^8)}}}