Question 469726
The discriminant, D is as follows:
given quadratic equation {{{ax^2 + bx + c = 0}}}
D = {{{b^2 - 4ac}}}
If D = 0, then there is only 1 real solution, specifically x = -b/2a
If D > 0, then there are exactly 2 real solutions
If D < 0, then no real solutions exist, graph never crosses x-axis
For this equation {{{5x^2 - 3x + 1 = 0}}}
a = 5
b = -3
c = 1
D = {{{(-3)^2 - 4(5)(1)}}} = {{{9 - 20}}} = {{{-11}}}
-11 < 0
Therefore, no real solutions exist for this equation