Question 469446
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Hi,
mixed to get 20 gallons
Let x and (20-x) represent the amount of the  35% and 25% solutions respectively
Question states*** 
 mixing to get 20 gal of 32% alcohol
   .35x + .25(20-x) = .32*20G
Solving for x
     .10x  = .07*20G =  
      x = 14G, the amount of the 35% Solution.  6G of the 25% solution

CHECKING our Answer***
.35*14 + .25*6  = 4.9 + 1.5 = .32*20 = .64