Question 469510
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Hi,
one car traveled, on average 8mph faster than the other car
Let x and (x + 8mph) represent the respective speeds of these cars
Question states*** Note:  D = r*t  OR t = D/r
   2x + 2(x+8) = 208
Solving for x
    4x = 192
      x = 48mph,  the faster car is traveling at 56mph  (44mph + 8mp)
CHECKING our Answer***
  96mi + 112m = 208mi