Question 469398
Given 4 sets of {1,2,3,4,5} 
Notice there are 3 odd (1,3,5) and 2 even (2,4)
Multiply by 4, which gives 12 odds and 8 evens in entire deck
So chance of picking an even number is 8/20= 2/5
With replacement:
Each selection is independent in this case, so probabilities remain constant
Probability of picking even on 1st card is 2/5
Probability of picking even on 2nd card is 2/5
{{{(2/5) * (2/5) = 4/25}}} 
Therefore probability of both cards being even is 4/25 or 0.16
Without replacement:
selections are not independent of each other, so probabilities may change
Probability of picking even on 1st card is 2/5
Now there is one less card in deck and one less even card
total = 19, even = 7, odd = 12
Probability of picking even on 2nd card is 7/19
{{{(2/5) * (7/19) = 14/95}}} 
Therefore probability of both cards being even is 14/95 or 0.147