<PRE><B>Question 48655</B>
A coin collector has $45 in quarters and dimes.  How many coins of each kind does he hae if the total number of his coins is 240?
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Quarter DATA:
number of quarters= x ; value of these quarters = 25x cents
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Dime DATA:
number of dimes= 240-x ; value of these dimes = 10(240-x)=2400-10x cents
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EQUATION:
value + value = value
25x + 2400-10x = 4500 cents
15x=2100
x=140 (number of quarters)
200-x=60(number of dimes)

Cheers,
Stan H.</PRE>