Question 469331
{{{sqrt(10-x)+x=-2}}}



{{{sqrt(10-x)=-x-2}}}



{{{10-x=(-x-2)^2}}}



{{{10-x=x^2+4x+4}}}



{{{0=x^2+4x+4+x-10}}}



{{{0=x^2+5x-6}}}



{{{x^2+5x-6=0}}}



{{{(x+6)(x-1)=0}}}



{{{x+6=0}}} or {{{x-1=0}}}



{{{x=-6}}} or {{{x=1}}}



Perform the check to find that only {{{x=-6}}} works.



So the solution is {{{x=-6}}}