Question 469275
{{{3x^2-4x-3 }}}.....use quadratic formula


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} ...note that {{{a=3}}}, {{{b=-4}}} and {{{c=-3}}}


{{{x = (-(-4) +- sqrt( (-4)^2-4*3*(-3) ))/(2*3) }}}


{{{x = (4 +- sqrt(16+36))/6 }}}


{{{x = (4 +- sqrt(52))/6 }}}


{{{x = (4 +- sqrt(4*13))/6 }}}


{{{x = (4 +- 2*sqrt(13))/6 }}}


{{{x = cross(4)2/cross(6 )3+- cross(2)*sqrt(13)/cross(6)3 }}}


{{{x = 2/3+- sqrt(13)/3 }}}


{{{x = (2+- sqrt(13))/3 }}}