Question 469115
Kim takes	x		hours						
Chris takes	x+	2	hours						
Kim does 1/x of the job in 1 hour						
Chris takes1/(x+	2)of the job in 1	hour			
Together they take 1/x+ 1/(x+2)of the job in 1hour			
Together they do the job in 2 8/9	hours					
Together they do  1/(2 8/9)	of the job in 1 hour			
1/x+1/(x+2)=1/(26/9)			
LCD =x(x+2)   							
(x+2)+x=	1/(26/9)(x^2+2)x	
( 2x+2)*	26/9	=(x^2+2x
5.83x+5.83	=	x^2+	2	x			
x^2	-3.83	x	-5.83	=	0				
Find the roots of the equation by quadratic formula									
									
a=	1	b=	-3.83	c=	-5.83				
									
b^2-4ac=	14.67	+	23.32						
b^2-4ac=	37.99			
sqrt(	37.99	)=	6.16		
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}									
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}									
x1=(	3.83	+	6.16	)/	2				
x1=	5								
x2=(	3.83	-6.16	) /	2					
x2= 	-1.17	
Ignore negative value							
Chris will take 5 hours