Question 469107
{{{P(x)=x^4-7x^3+13x^2+3x-18 }}}
{{{x^4-7x^3+13x^2+3x-18 =(x^4-2x^3)+(-5x^3+10x^2)+(3x^2-6x)+(9x-18)=x^3(x-2)-5x^2(x-2)+3x(x-2)+9(x-2)=(x-2)(x^3-5x^2+3x+9)}}}
e.(x-2)(x^3-5x^2+3x+9)