Question 469098
Let r,a be initial radius and area
Let R,A be increased radius and area
R = r + 0.3r (0.3*r = 30% of r)
R = 1.3r
a = {{{(pi*r^2)/2}}}
A = {{{(pi*R^2)/2 =(pi*(1.3r)^2)/2 = 1.3^2*(pi*r^2)/2 = 1.3^2*a}}}
1.3^2 = 1.69
A = a + 0.69a
Therefore area increased by 69%