Question 469032
Use Pythagorean theorem:
a^2 + b^2 = c^2
Let x be length of other leg, then hypotenuse is (x+4).
{{{x^2 + 8^2 = (x+4)^2}}}
{{{x^2 + 64 = x^2 + 8x + 16}}}
{{{48 = 8x}}}
{{{6 = x}}}
Therefore, the other leg is 6 and the hypotenuse is 10.