Question 48571
looks like an error in the working out of the fractional value of c.


2x-3y=4
2x-4=3y
3y=2x-4
y=(2/3)x-(4/3)


Its gradient is 2/3. As our line is parallel, its gradient is also 2/3. So we have:


y=mx+c
y=(2/3)x+c


We also know that the line passes through (-5,4), so we then get:
4=(2/3)(-5)+c
4=(-10/3)+c
c = 4+(10/3)
c = (12/3)+(10/3)
c = 22/3


--> y=(2/3)x+(22/3)


jon