Question 468521
two numbers differ by 10. The larger number is 6 less than twice the smaller number. Find the numbers.

Solution;
let x - the larger number
y - the smaller number

from the first phrase,
 x - y = 10 ---- (1)

from the second phrase,
 x = 2y - 6 ----(2)

then, substitute the value of x in (2) into (1),

2y - 6 - y = 10
y = 10 + 6
y = 16

for x:
x = 2y - 6
x = 2(16)-6
x = 26

and finally,

x = 26 and y = 16 <----- answer

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