Question 468507
x² - x + 1 = 0 
a = 1, b = -1, c = 1 


-b ± √(b² - 4ac)
---------------- = x {the quadratic formula}
2a


-(-1) ± √[(-1)² - 4(1)(1)]
--------------------------- = x {substituted into quadratic formula}
2(1)


1 ± √(1 - 4)
------------- = x {simplified}
2


1 ± √-3
--------- = x {subtracted 1 and -4}

2


1 ± √-1 √3
----------- = x {broke the -3 into -1 and 3, because you can't take square root of negative number}
2


1 ± i√3
-------- = x {using imaginary numbers, the square root of -1 is i}
2
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