Question 468482
10x - 3y = 60 


To find the x-intercept (where the line crosses the x-axis), put 0 in for y:
10x - 3y = 60 
10x - 3(0) = 60 {substituted 0 in for y}
10x = 60 {multiplied -3 by 0}
x = 6 {divided both sides by 10}
x-intercept is 6
coordinates of x-intercept are (6,0)


To find the y-intercept (where the line crosses the y-axis), put 0 in for x:
10x - 3y = 60
10(0) - 3y = 60 {substituted 0 in for x}
-3y = 60 {multiplied 10 by 0}
y = -20 {divided both sides by -3}
y-intercept is -20
coordinates of y-intercept are (-20,0)
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