Question 48545
For the function defined by f(x)=2-x^2, 0<=x, use a sketch to help find a formula for f^-1(x). 
My possible answers to choose from are: 
a. f^-1(x)=x^2-2, x<=2
b. f^-1(x)=1/2-x^2, 0<=x
c. f^-1(x)=sqrt2+sqrtx, 0<=x
d. f^-1(x)=sqrt 2-x, 0<=2

Given function Y=2-x^2, 0<=x
Find the inverse:
x=2-y^2
y^2=2-x
y=sqrt(2-x), x<=2
This is the inverse.

Cheers,
Stan H.