Question 468414
{{{y=3x^2+6x-12}}}......standard form 

When a function is in standard form rather than vertex form , we cannot simply look at the function and find the vertex of (h, k). There are two ways to approach this problem.

    Using a formula: The x-value of the vertex can be found using the formula {{{h=-b/2a}}} y-value. 

{{{y=3x^2+6x-12}}}......{{{a=3}}}, {{{b=6}}} and {{{c=-12}}}

{{{h=-b/2a}}} 

{{{h=-6/2*3}}} 

{{{h=-6/6}}} 

{{{h=-1}}} 

{{{y=3x^2+6x-12}}}

{{{y=3(-1)^2+6(-1)-12}}}

{{{y=3(1)-6-12}}}

{{{y=3-18}}}

{{{y=-15}}}

the vertex is (h, k)=(-1, -15)

{{{ graph( 500, 500, -10, 10, -20, 10, 3x^2+6x-12) }}}