Question 468323
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
y = x^2 + 4x – 1
f(x)= (x+2)^2 -4 - 1
f(x)= (x+2)^2 -5  V(-2,-5) minimum  a =1 a>0 Parabola opens upward
                    Line of symmetry x = -2

{{{drawing(300,300,  -20,20,-20,20,  blue(line(-2,20,-2,-20))  , grid(1),
circle(-2, -5,0.6),
graph( 300, 300, -20,20,-20,20,0, x^2+4x-1 ))}}}