Question 48026
Your answer would be  x^4yz/3.
If you bring x^-1 to the numerator that would be 3x^3(x^1)y^4z^-2/6y^3z^-3
   so simplified it would be 3x^4y^4z^-2/6y^3z^-3.
Now simplify the z's.
   bring z^-3 to the numerator. And get 3 x^4 y^4 z^-2(z^3) /6y^3
   Simplified is 3x^4 y^4 z/ 6y^3
Now y's, bring y^3 to the numerator and get 3x^4 y^4(y^-3) z/ 6 
   Simplified is 3x^4 y z/6
Now the numbers 3/6 can be simplified to 1/3

and get  x^4yz
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           3

z^-2(z^3) is z because when multiplying your exponents add or subtract depending on whether a number is negative or positive. In this problem its like (-2+3)= 1 and z^1 is z