Question 461497
The sum of three numbers is 65. One number is 10 more than the second number. It is also twice the third. Find each of the three numbers.
...
let x=first number
x-10=second number
x/2=third number
..
x+x-10+x/2=65
2x+x/2=75
4x+x=150
5x=150
x=30
..
ans:
first number=30
second number=x-10=30-10=20
third number=x/2=30/2=15