<PRE><B>Question 468210</B>
A trucker traveled 160 miles in one direction during a snow storm. The return trip in rainy weather was accomplished at double the speed and took 5 hours less time. Find the speed going
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1st leg DATA:
distance = 160 miles ; rate = r mph ; time = d/r = 160/r hrs
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Return leg DATA:
distance = 160 miles ; rate = 2r mph ; time = 160/(2r) hrs
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Equation:
1st time - 2nd time = 5 hrs
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160/r - 160/(2r) = 5 hrs
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Multiply thru by 2r to get:
320 -160 = 10r
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160 = 10r
r = 16 mph (1st leg speed)
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2r = 32 mph (2nd leg speed)
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Cheers,
Stan H.
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