Question 468086
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Hi,
Let x, (x+2) and (x+4) represent the three positive consecutive even integers 
Question states***
 x(x+4) = [x + {{{highlight(x+2)}}} + (x+4)] + 150
Solving for x
 x^2 + 4x = 3x + 156
 x^2 + x  - 156 = 0
factoring
(x +13)(x-12) = 0
(x +13)= 0   x = -13  Extraneous solution
(x-12) = 0   x = 12
the three positive consecutive even integers are 12,14,16

CHECKING our Answer***
 12*16 = 192 = 42 + 150  = 192