Question 468022
That's too many problems.
Repost with your answers, and I'll check them for you.
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I'll do one.
(x-5)^2+2(x-5)-35=0 
Sub y for x-5
y^2 + 2y - 35 = 0
(y+7)*(y-5) = 0
y = -7, 5
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x-5 = -7 --> x = -2
x-5 = 5 --> x = 10