Question 468017
"what is the perimeter of a right triangle with its legs measuring 7 and 24"


Pythagorean Theorem
a² + b² = c² {a and b are the legs and c is the hypotenuse}
7² + 24² = c² {substituted into Pythagorean Theorem}
49 + 576 = c² {squared 7 and 24}
625 = c² {combined like terms}
c = 25 {evaluated square root of 625 to be 25}


Perimeter of a triangle = all sides added together


Perimeter = 7 + 24 + 25
= 56
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