Question 467918
2x-7=2/x

x(2x-7) = 2
2x^2 -7x -2 = 0
Solve using quadratic equation where:
a = 2
b = -7
c = -2

x = [-b +/- (b^2 - 4ac)^1/2] / 2a
x = [-(-7) +/- (-7^2 - 4*2*(-2)] / 2(2)
x = [7 +/- (49 + 16)^1/2] / 4
x = [7 +/- 8.06] / 4
x = 3.766
x = -0.265