Question 48504
{{{-x^2 + 8x < 19}}}
{{{-x^2 + 8x - 19 < 0}}}
v(4,-3) The vertex is located in the fourth quadrant. Since it is below the x-axis and the parabola opens downward and the values are less than zero (negative values), the solution is all real solutions.
{{{graph(600,600,-10,10,-10,10,-x^2+8x-19,0)}}}