Question 467666
There are a total of 41 workers {{{24 + 17 = 41}}}
A total of 8 are chosen, thus the total number of combinations is (41 C 8)
41 C 8 = {{{(41!)/(8!(41-8)!)}}}
6 out of 24 are chosen among the first-shift workers
The number of combinations of choosing 6 out of 24 is (24 C 6)
24 C 6 = {{{(24!)/(6!(24-6)!)}}}
2 out of 17 are chosen among the 2nd-shift workers
The number of combinations of choosing 2 out of 17 is (17 C 2)
17 C 2 = {{{(17!)/(2!(17-2)!)}}}
The desired probability is the number of combinations of 6 1st shift workers and 2 2nd shift workers divided by the total number of possible 8-worker combinations
=> {{{P = (24 C 6)(17 C 2)/ (41 C 8)}}}