Question 48489
I get 2 real solutions
The discriminant is
{{{0 +- sqrt( b^2-4*a*c )}}}
Now to find a,b, and c
{{{4x^2 -6x  = 4}}}
{{{x^2 -(3/2)*x -1 = 0}}}
a = 1
b = -3/2
c = -1
{{{0 +- sqrt( (-3/2)^2-4*1*(-1) )}}}
{{{0 +- sqrt(9/4 + 16/4) }}}
{{{0 +- sqrt(25/4)}}}
{{{0 +- 5/2}}}
There are 2 real roots since the values of the 
discriminant are +5/2 and -5/2