Question 467484
am having trouble figuring out how to solve (6x^2y^4)^1/2. I was able to solve (x^2y^4)^1/2, which is xy^2 but not sure how to solve for 6.
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 (6x^2y^4)^1/2=xy2√6
you need to leave 6 in radical form or 6^1/2