Question 467427
-2x + 5y = 15


At the x-intercept (where the line crosses the x-axis), y is 0.
To find the x-intercept, substitute 0 in for y:
-2x + 5y = 15
-2x + 5(0) = 15 {substituted 0 in for y}
-2x = 15 {multiplied 5 by 0}
x = -15/2 {divided both sides by -2}
x-intercept is -15/2.....the coordinates are (-15/2,0) 


At the y-intercept (where the line crosses the y-axis), x is 0.
To find the y-intercept, substitute 0 in for x}
-2x + 5y = 15
-2(0) + 5y = 15 {substituted 0 in for x}
5y = 15 {multiplied -2 by 0}
y = 3 {divided both sides by 5}
y-intercept is 3.....the coordinates are (0,3)
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